# Integer Sequence Reviews: A075771, A032799, A002717

It’s been almost two years since I last sat down with my friend David Cushing and did what God put us on this Earth to do: review integer sequences.

This week I lured David into my office with promises of tasty food and showed him some sequences I’d found. Thanks to (and also in spite of) my Windows 10 laptop, the whole thing was recorded for your enjoyment. Here it is:

I can only apologise for the terrible quality of the video – I was only planning on using it as a reminder when I did a write-up, but once we’d finished I decided to just upload it to YouTube and be done with it.

We reviewed the following sequences:

#### A075771 Let $n^2 = q \times \operatorname{prime}(n) + r$ with $0 \leq r \lt \operatorname{prime}(n)$; then $a(n) = q + r$.

1, 2, 5, 4, 5, 12, 17, 10, 15, 16, 31, 36, 9, 28, 41, 48, 57, 24, 31, 50, 9, 16, 37, 48, 49, 76, 15, 42, 85, 116, 79, 114, 137, 52, 41, 96, 121, 148, 27, 52, 79, 144, 139, 16, 65, 136, 109, 84, 141, 220, 49, 86, 169, 166, 209, 254, 33, 124, 169, 240, 55, 48, 297, 66

#### A032799 Numbers $n$ such that $n$ equals the sum of its digits raised to the consecutive powers $(1,2,3,\ldots)$

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 89, 135, 175, 518, 598, 1306, 1676, 2427, 2646798, 12157692622039623539

#### A002717 $\lfloor n(n+2)(2n+1)/8 \rfloor$

0, 1, 5, 13, 27, 48, 78, 118, 170, 235, 315, 411, 525, 658, 812, 988, 1188, 1413, 1665, 1945, 2255, 2596, 2970, 3378, 3822, 4303, 4823, 5383, 5985, 6630, 7320, 8056, 8840, 9673, 10557, 11493, 12483, 13528, 14630, 15790, 17010, 18291, 19635, 21043, 22517

• #### Christian Lawson-Perfect

Mathematician, koala fan, Aperiodical editor. Usually found paddling in the North Sea, or fiddling with computers.
• #### David Cushing

Mathematician / magician / origami enthusiast. Wanted for fraud in at least one branch of Subway.

### 2 Responses to “Integer Sequence Reviews: A075771, A032799, A002717”

1. John

I generated A075771 up to n = 5,761,455 and counted repeats. It seems that the more times a number appears in the sequence, the more likely it is to be square.